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The potentiometer is clear, but the 2. Post as a guest Name. Email Required, but never shown. It appears to be reversed. That means there is a small current flow out from the pin. How does doing anything ah6884 pin 7 or pin 8 affect that?
There is also no discharge path with your arrangement. Home Questions Tags Users Unanswered.
Sign up or log in Sign up using Google. Can someone explain what the reversed capacitor is doing here? It’s the DC bias determine the polarity.
Most people use “low” to refer to either a lower voltage, or a lower position on the diagram. Pin 7 is the output of the internal amplifier, and pin 8 is its input, designed to accept a low-level AC input 57 mV for a 0-dB indication.
Reverse biased capacitor on IC input pin Ask Question.
AN6884 Datasheet PDF
Per AN’d datasheet na6884, Pin 8 is the signal input pin, and it’s the internal Op amp’s positive input.
AN Datasheet(PDF) – Panasonic Semiconductor
Indeed, it must in order for any of the LEDs to turn on! Placing it at a higher voltage within the datasheet’s max specified V will both lower the amplification and raise the lower rail of the comparators in the block diagram. It just shortens the range of turn over which the potentiometer works.
That is to say that the LEDs all come on at a much smaller turn of the potentiometer. As displayed, the LEDs go from fully off to fully on over roughly the entire turn range of the potentiometer. However, if that’s the case, I can’t explain why reversing the capacitor doesn’t work, unless the actual polarity of the capacitor datawheet backwards from datasheer you think it is. If I “correct” the orientation, the circuit does not work at all.
So it determines the DC bias of the block capacitor’s polarity. I will be certain to use them here from now on. If I remove the 2. This circuit will light the LEDs as the input voltage on pin 8 increases relative to pin 7.
Your description doesn’t agree with that in the datasheet. Per AN’d datasheet. Right, I get that pin 7 is the output of the amp, but it’s part of the negative feedback loop on the amp. Sign up using Facebook. The diode will mess up the response of the chip due to its forward voltage drop.
I know the correct names, but I conversely find “inverting” and “noninverting” confusing when dealing with comparators, since those terms make more sense when dealing with op-amps. Passing Vin through a reverse capacitor seems to be potentially more prone to failure. The LED pins connect to the negative side of the LEDs, and the pins go low when the output of the internal amp goes above Vref dropped by voltage dividing resistors at each comparator.
Capacitor with polarity can be used ac couple or blocking. To be clear, removing the capacitor doesn’t light up the LEDs all at once.
(Datasheet) AN pdf – 5-Dot LED Driver Circuit (1-page)
By “low side”, you’re referring to the inverting inputs of the comparators. Sign up using Email and Password. Vref is the high side of the 5 LED comparators in the datasheet block diagram.